I am trying to estimate a binomial experiment, P[X=4] using the normal distribution. Can I do this? Because I know the fact that the P(any single #) for normal is 0. Is there a trick for this? I am trying to estimate a binomial experiment, P[X=4] using the normal distribution. Can I do this? Because I know the fact that the P(any single #) for normal is 0. Is there a trick for this? @Mathematics
the trick is to accomodate for the continuous nature of the normal when approximating the discrete nature of the binomial
the trick itself is to take values that are the average between discretes
Is that the half unit correction?
yes
mean = np variance = npq sd = sqrt(var)
Well I've got that, but the question I have would be if this is correct. If I were to take the z probability up to 4, which is a z statistic of -.97. If I were to take the value under that, wouldn't that be the probability of 0, 1, 2, 3 and 4? I want to use it to find the exact value at 4, but I know the integration will be 0 for that...
what are the number of trials: n and the prob of success: p ??? without those I got no idea
the normal is an approximation; therefore trying to find the exact value at 4 is a bit harsh
n=20, p=.3, q=.7 . The P(X=4)= .130, as I've found from the binomial table
to be exact, youd have to do it with the binomial distribution
That's what I thought! But the question asks for us to do it using the normal distribution. All the questions before it were ranges, but this one is a value, so that's what threw me...
mean = 6 ; sd = sqrt(4.2) the value under 4 would be: z = (3.5-6)/sqrt(4.2) = -1.22 as the test statistic
Yeah, I've got that. But I question if the area to the right of this is really the probability of X=4. It seems like it would be the probability of X<=4
i see your point; if its less and equal to 4 then we use the 4.5 if i recall correctly
does the question sate less then 4 or less than equal to 4?
*state
less than 4 I get .1112 <=4 i get .2327 maybe
No, it is straight =, it is P(x=4), using the normal.
well, equals is just the prob area between 3.5 and 4.5 subtract the normals of 3.5 and 4.5 to approx the bi@4
Ah, thanks!!
yep
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