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A = Pert, where P is the initial investment and r is the interest rate. 1.How long will it take for $2000 to double if it is invested at 13% interest compounded continuously? 2.What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years?
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perts double in ln(2)/r
ln(900/500)/10 is the rate of the other
can i get some kind of steps?
A = Pe^rt ; divide off the P A/P = e^rt ; ln the sides ln(A/P) = rt ; and depending on what your looking for, divide of the rate or the time to solve
I thought the algebra was self evident ....
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