Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (frenchy):

Find the derivative of inversetan(x) ?

OpenStudy (anonymous):

it should be right in your text. are you trying to get it from scratch?

OpenStudy (frenchy):

no not from the definition just the shortcut of what it is

OpenStudy (agreene):

\[\frac{d}{dx} \tan^{-1}x=\frac{1}{x^2+1}\] this should be one that you just know.

OpenStudy (frenchy):

okay, i see. thank you!

OpenStudy (frenchy):

wow, this thing is pretty awesome..

OpenStudy (frenchy):

(newbie)

OpenStudy (anonymous):

what agreen said

OpenStudy (agreene):

Yeah! what i said! :D

OpenStudy (anonymous):

it is hard to do using the definition, but not hard if you know that \[\frac{d}{dx}f^{-1}(x)=\frac{1}{f'(f^{-1}(x))}\]

OpenStudy (anonymous):

Which you can get from \[f(f ^{-1}(x))=x\]. This is what i usually remember.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!