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Find the derivative of inversetan(x) ?
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it should be right in your text. are you trying to get it from scratch?
no not from the definition just the shortcut of what it is
\[\frac{d}{dx} \tan^{-1}x=\frac{1}{x^2+1}\] this should be one that you just know.
okay, i see. thank you!
wow, this thing is pretty awesome..
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(newbie)
what agreen said
Yeah! what i said! :D
it is hard to do using the definition, but not hard if you know that \[\frac{d}{dx}f^{-1}(x)=\frac{1}{f'(f^{-1}(x))}\]
Which you can get from \[f(f ^{-1}(x))=x\]. This is what i usually remember.
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