Question

x has a normal distribution with a mean of 80.0 and a standard deviation of 4.0. Find the following probabilities:
(A) P(x <79.0)
(B) P(78.0 86.0) Here is my work so far, I am not sure if you can have a negative probability, can you?: mean=80.0 standard deviation=4.0 (A) P(x<79.0) 79.0-80.0/4.0 -1/4.0 -0.25 P(x<79.0)=P(z<-0.25) =0.0987-5.000=-0.4013 (B) P(78.086.0) z=x-mean/stan dev z=86.0-80.0/4.0=6/4.0=1.5 P(x>86.0)=P(z>1.5) =0.4332+0.5000=0.9332 x has a normal distribution with a mean of 80.0 and a standard deviation of 4.0. Find the following probabilities: (A) P(x <79.0) (B) P(78.0 86.0) Here is my work so far, I am not sure if you can have a negative probability, can you?: mean=80.0 standard deviation=4.0 (A) P(x<79.0) 79.0-80.0/4.0 -1/4.0 -0.25 P(x<79.0)=P(z<-0.25) =0.0987-5.000=-0.4013 (B) P(78.086.0) z=x-mean/stan dev z=86.0-80.0/4.0=6/4.0=1.5 P(x>86.0)=P(z>1.5) =0.4332+0.5000=0.9332 @Mathematics