Question

dff wrt x : f=arctan(3y/x)

Answer 1

use method as I showed you in your previous question, let w = 3y/x and then differentiate by parts.

Answer 2

i did that just want to be sure

Answer 3

what answer did you get?

Answer 4

z=arctan(3y/x)

w=3y/x
then:
z=arctan(u)
dz/dx=dz/dw∗dw/dx=arctan(u)∗-3yx^-2

Answer 5

right?

Answer 6

@ asnaseer is arctanu= 2arctan[x/1+\[\sqrt{1+x^2}\][3y] ?

Answer 7

are u dre?

Answer 8

sorry I was called away just got back

Answer 9

you got dz/dw wrong

Answer 10

it should be 1/(1+w^2)

Answer 11

\[y=arctan(x)\]\[dy/dx=\frac{1}{1+x^{2}}\]

Answer 12

Okay. Thanks.