Divide.
(x^6-8x^3+15)÷(x^3-3)

Question

anonymous · Answer

x^3-5

anonymous · Answer

Hint: for a problem like this, always see if you can factor the numerator and/or denominator. In this case, since the denominator can't be factored, there's a really good chance that (x^3-3) is the same as one of the factors of the numerator. (and it is) So, with this hint, factor, the numerator, then you can cancel out the common factors...

anonymous · Answer

x^3 - 5

anonymous · Answer

Sorry that others decided to feed you the answer rather than explaining the thought process

anonymous · Answer

You can find the factors and cancel them or you can find the quotient by long division method.

anonymous · Answer

lol the answer is what i wanted.

anonymous · Answer

Thx 4 explaining it tho.

anonymous · Answer

But the answer won't help the next time you encounter a similar problem

anonymous · Answer

Problems like this are usually very contrived, in other words, set up such that there are one or more common factors in the numerator and denominator, so always look for this.