Divide. (x^6-8x^3+15)÷(x^3-3)
x^3-5
Hint: for a problem like this, always see if you can factor the numerator and/or denominator. In this case, since the denominator can't be factored, there's a really good chance that (x^3-3) is the same as one of the factors of the numerator. (and it is) So, with this hint, factor, the numerator, then you can cancel out the common factors...
x^3 - 5
Sorry that others decided to feed you the answer rather than explaining the thought process
You can find the factors and cancel them or you can find the quotient by long division method.
lol the answer is what i wanted.
Thx 4 explaining it tho.
But the answer won't help the next time you encounter a similar problem
Problems like this are usually very contrived, in other words, set up such that there are one or more common factors in the numerator and denominator, so always look for this.
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