4√4x^2y * 4√8x^6y^3 4√4x^2y * 4√8x^6y^3 @Mathematics

Question

anonymous · Answer

Square Root is for which numbers?

anonymous · Answer

just retype it here using equation editor

anonymous · Answer

Yes, try using Equation button.

anonymous · Answer

$$\sqrt[4]{4x^2} * \sqrt[4]{8x^6y^3}$$

anonymous · Answer

oops in the 4x^2 there's a y after that as well

anonymous · Answer

ew. to 4th power

anonymous · Answer

ya it's not fun, my teacher gave this to us for homework but hasn't taught us how to do it :/

anonymous · Answer

are u sure it isnt cubed root?

anonymous · Answer

Positive. It's deff 4th root

anonymous · Answer

$$2x ^{2}\sqrt[4]{2y}$$

anonymous · Answer

$$8x^{2}y$$

anonymous · Answer

my answer is wrong. forgot the y

anonymous · Answer

how do you get your answer? I have a horrible teacher so I'm still a bit lost with the whole root to the power thing :(

anonymous · Answer

im not sure how abdul got 8... but the answer i got was 
$$2x^2y \sqrt[4]{2}$$

anonymous · Answer

How did you get that MJ?

anonymous · Answer

because they are both to the 4th root, and they are all multiplication you can just multiply whats under the radical and get $$\sqrt[4]{32x^8y^4}$$ 32 can be factored into 16*2 16, is 2^4 so you can pull a 2 out and leave a 2 in to get $$2\sqrt[4]{2x^8y^4}$$

anonymous · Answer

$$\sqrt[4]{x^8}=x^2$$
$$\sqrt[4]{y^4}=y$$

anonymous · Answer

putting it all together gets $$2x^2y \sqrt[4]{2}$$

anonymous · Answer

Ok, I'm going to trust you MJ lol, I hope you're right :)

anonymous · Answer

root of 4 can be rewritten as 4^1/2
$$\sqrt[4]{4x^22y*8x^6y^3}$$
$$32^{1/4}*x ^{2}*2^{1/4}*y$$

anonymous · Answer

abdul why is there 32 and a 2?

anonymous · Answer

4*8 = 32 not 64

anonymous · Answer

oh wow
never mind i cant read

anonymous · Answer

the real answer is $$4x^2y$$
i didnt see that it was 2*y in first problem

anonymous · Answer

$$64^{1/2}x^2y$$

anonymous · Answer

wait no i was right the first time ><

anonymous · Answer

abdul that 2 you were seeing was the x^2 <- that one

anonymous · Answer

Oh, total mess up, I took that to be 2y. Sorry.. :(

anonymous · Answer

Oh not it's okay, it's my fault I forgot to put it in the equation :/

anonymous · Answer

So you guys, if I have $$\sqrt[4]{32x^9}$$ am i going to take the 32/ 4?

anonymous · Answer

What is that power, x^?

anonymous · Answer

9

anonymous · Answer

32^1/4*(x^9)^1/4

anonymous · Answer

you factor 32 
in this case 16*2 works the best

anonymous · Answer

but what do I do with the 9?

anonymous · Answer

It would become x^9/4

anonymous · Answer

Ah gottcha!