Question

ho to differentiate y= (lnx)^5 ho to differentiate y= (lnx)^5 @Mathematics

Answer 1

you can do it by parts, first ley w=lnx so you get:\[y=w^5\]then use the rule:\[dy/dx=dy/dw*dw/dx\]you should be able to solve this now

Answer 2

Use the power rule:
y = (lnx)^5
let u = lnx
du/dx = 1/x
y = u^5
dy/du = 5u^4 du/dx
dy/dx = (5/x)(lnx)^4

Answer 3

thanks....