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Physics 10 Online
OpenStudy (anonymous):

A car goes around a curve on a road that is banked at an angle of 34.5^\circ . Even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 18.0 m/s. What is the radius of the curve? A car goes around a curve on a road that is banked at an angle of 34.5^\circ . Even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 18.0 m/s. What is the radius of the curve? @Physics

OpenStudy (anonymous):

OpenStudy (anonymous):

Your formula wont work because we are not givin mass. we only have the tangle of the banked turn and the speed

OpenStudy (anonymous):

Oops! multiply v^2/rho by m. then re-solve.

OpenStudy (anonymous):

It will become \[\rho = {v^2 \over g \sin(\theta)}\]

OpenStudy (anonymous):

Nop\[R=v ^{2}\div g \tan (\theta)\]e i got the right answer after, the formula is

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