F(x)=^3sqrt(x-1) +4 Find f^-1(x) ........ HELP!!!!
is this the correct equation?\[f(x)=3\sqrt{x-1}+4\]
asnaseer if u could help me with my latest probs that would be awesome man!
yea
ok, then what you need to do is invert this so you end up with x = ...
you can do this steps
"in steps"
so u end up with [x=\sqrt[3]{x-1}+4\]
for x and the same for y
no - let me try and do it step-by-step for you
alright thank you
\[f(x)=3\sqrt{x-1}+4\]take 4 away from both sides to get:\[f(x)-4=3\sqrt{x-1}\]square both sides to get:\[(f(x)-4)^2=(3\sqrt{x-1})^2=9(x-1)\]divide both sides by 9 to get:\[\frac{(f(x)-4)^2}{9}=x-1\]add 1 to both sides to get:\[\frac{(f(x)-4)^2}{9}+1=x\]finally swap the left-hand and right-hand sides to get the answer:\[x=\frac{(f(x)-4)^2}{9}+1\]the usual practice is to then replace x on the LHS with f-1(x) and replace the f(x) on the RHS with x to get the inverse function:\[f^{-1}(x)=\frac{(x-4)^2}{9}+1\]
hope that makes sense.
thank you!! :))
no problem - glad to be of service :-)
Join our real-time social learning platform and learn together with your friends!