Question

Find the derivative of:
y=squareroot((x^(2)+9)/(x+3) @Mathematics

Answer 1

\[y=\sqrt{(x ^{2}+9)\div(x+3)}\]

Answer 2

ick

Answer 3

I know it is getting me so confused

Answer 4

it will be
\[\frac{1}{2\sqrt{\frac{x^2+9}{x+3}}}\times \frac{d}{dx}\frac{x^2+3}{x+3}\]

Answer 5

second part you get from the quotient rule

Answer 6

and of course the first part is
\[\frac{\sqrt{x+3}}{2\sqrt{x^2+9}}\]

Answer 7

I think it the derivative is equal to zero

Answer 8

i made a typo in the first line, second part should be
\[\frac{d}{dx}\frac{x^2+9}{x+3}\]
and that derivative is
\[\frac{x^2+6x-9}{(x+3)^2}\] by the quotient rule

Answer 9

you have to set this equal to zero??

Answer 10

NOpe

Answer 11

good

Answer 12

factor x^2+6x+9
(x+3)^2

Answer 13

So th etop and bottome cross each other out and it becomes 1

Answer 14

no there is no
\[x^2+6x+9\] in it. it is
\[x^2+6x-9\]

Answer 15

OH I wish it was +9

Answer 16

Thanks for your help ;D