use the continuity of the exponential function to show that lim x->0 of (1+tx)^(1/x) = e^t use the continuity of the exponential function to show that lim x->0 of (1+tx)^(1/x) = e^t @Mathematics
\[\lim_{x \rightarrow 0}(1+tx)^{1/x} = e^t\]
I don't know how to use the continuity of the exponential function to show this
i guess i don't either. the limit is easy enough, but not sure what the question wants
how can I show that the limit equals e^t? can I do it without using the definition of e?
without the definition of e it doesn't even make sense. i would say \[(1+xt)^{\frac{1}{x}}=e^{\frac{1}{x}\ln(1+xt)}\] and then take the limit in the exponent. maybe that is what the question is asking for, because that does in fact use "the continuity of the exponential function"
show that \[\lim_{x\rightarrow 0}\frac{1}{x}\ln(1+xt)=t\] and you will have your solution
that's actually perfect! exactly what I was looking for, thank you
oh good. yw
and solve via l'hopital i guess
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