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Is it convergent? if so find its Sum. 1+3^n/2^n
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not convergent
why?
its you can rewrite it as 1 + (3/2)^n
and (3/2) > 1 so its divergent
\[\sum_{n=1}^{\infty} ( 1+3^{n})/(2^n)\] is the proper problem the 1is attached to the 3^n
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you can rewrite it as this: (3/2)^n+2^(-n) its this divergent because(3/2)>1 and if one of the 2 is divergent you dont have to calculate the other because it will be divergent
ok. thanks
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