Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = x^5 - 2x^2 + 4x + 3
The possible rational zeros are fractions of the form p/q where p is a factor of the last term 3 and q is a factor of the first coefficient 1 (of x^5) So the possible rational zeros are: 3/1, -3/1, 1/1, -1/1 which reduce to: 3, -3, 1, -1
that's a neat theorem to learn. does this mean, since there are only 4 rational roots and we have a 5th degree polynomial, that the last root is imaginary/irrational?
no, imaginary roots come in pairs so if the last root is imaginary, then you'll only have 3 rational roots (since you'll really have 2 imaginary roots)
and those are the POSSIBLE rational roots
D'oh! of course, so the last root must be irrational? ah, I see from your last reply that the last root could also be rational
Ie, if there is a rational root, then it is one of those four values
it's perfectly possible to have 5 rational roots (you can easily have a double/triple root)
nowhere does it say we have to use each root once, those are just the only candidates we can use
Ok - I think I understand the principal now. thanks for the insight!
np
its a necessary condition , if f(x) = 0 where x= p/q , then it must be of the form above
then p divides the last term, and q divides the first term
but theres no guarantee there is any p/q such that f(p/q) = 0 . But if it exists , then it must be of the form above
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