Question

: You have an audio file of a 8.00 minute song. The song is sampled at 60.0 KHz with each sample taking 16 bits. What is the size of the audio file? Give your answer in Kbytes. , , @Physics

Answer 1

8 minutes = 8 * 60s = 480s
60 khz = 60,000 samples per second

Your total samples are 480 * 60000 = 28800000

Each sample takes 2 bytes (16 bits) so you end up with 57,600 kbytes

Answer 2

oh lol thanks, for the samples per sec i used the lossless compression rate, so I used 2*60k = 120k samples per sec. but what you have is the answer according to my homework console. :D

Answer 3

Well I geuss that's good. I've never been asked to calculate it before :)

Answer 4

Lossless or not, you should still be using 60,000 since that's all the samples you're taking every second

Answer 5

hahah props to you skills :D i would not know how to answer this on the first time i see it. but there was a question too that asked for how many samples per second should be taken for lossless compression, and the right way was to multiply the frequency by 2 and that should be the samples taken per second, so yeah.. :D

Answer 6

Ok, can see that for that question :)

Answer 7

err *I can see*...

Answer 8

haha yeah. thanks again!! :D

Answer 9

n p :)

Answer 10

Use dimensional analysis. Each fraction is equivalent to 1, because they are the relevant conversion factors for the given units. The units all cancel and you are left with kb.
\[8\min \times \frac{60s}{1\min} \times \frac{60,000samples}{1s} \times \frac{2bytes}{1sample} \times \frac{1kb}{1024bytes}\]

Answer 11

Good point..I should have done that. If I had, I would have realized that I needed 1024 vs 1000 bytes per kb :) So my answer is slightly off

Answer 12

For the record, it should have been 56,250 kb