Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

How do i find the slope of these data?

OpenStudy (anonymous):

Time (s) 0.0 0.10 0.20 0.30 0.40 0.50 0.60 Position (cm[W]) 0 25 50 75 75 75 0

OpenStudy (anonymous):

I tried this: (0.60, 0.0)(0.50, 75 cm) m = 0.0 - 75 cm ----------- 0.60s - 0.50s = -75 cm -------- 0.1s = -750 cm/s

OpenStudy (amistre64):

slope between any 2 points (a1,a2) and (b1,b2) is simply the ratio of the differences between them: \[\frac{a2-b2}{a1-b1}\]

OpenStudy (anonymous):

yup, it is. But somehow I feel like my answer is wrong.

OpenStudy (amistre64):

no, its good; the math dont lie

OpenStudy (amistre64):

at that end its a negative slope since it goes from high to low

OpenStudy (anonymous):

also, if I want to find the slope from 0.0s - 0.30s how can I put the coordinates together/

OpenStudy (amistre64):

same way; the formula for slope doesnt change simply becasue the number change

OpenStudy (anonymous):

also

OpenStudy (amistre64):

\[\frac{change.in.position}{change.in.time}\]

OpenStudy (anonymous):

I tried to find the slope from 0.0 s - 0.30s, and I did this: (0.30s, 0.0s)(0.30s, 75 cm) m = 75 - 0.0 ------- 0.30 - 0.30 = n/a

OpenStudy (amistre64):

time changes from 0.0 to 0.3; not from 0.3 to 0.3

OpenStudy (amistre64):

.3-0 = .3 for your denominator

OpenStudy (anonymous):

I tried the y2-y1/x2-x1

OpenStudy (anonymous):

and if I plot (0.30, 0.0) (0.30, 75)

OpenStudy (amistre64):

you tried yes; but you simply inserted the numbers wrong. keep an eye on that :)

OpenStudy (amistre64):

your first plot is (0,0) NOT .. (.3,.3)

OpenStudy (amistre64):

well, i typoed that up dint i

OpenStudy (anonymous):

ohhh, noo D;

OpenStudy (amistre64):

your first plot is (0,0) NOT .. (.3,0) thats better lol

OpenStudy (anonymous):

why will my first plot be (0,0)

OpenStudy (amistre64):

at time = 0, what is your position?

OpenStudy (amistre64):

"if I want to find the slope from 0.0s - 0.30s how can I put the coordinates together" what is the (t,P) at 0? what is the (t,P) at .3?

OpenStudy (anonymous):

ohhh...

OpenStudy (anonymous):

so the t = 0.0s and position is 0 cm t - 0.30s and position is 75 cm

OpenStudy (amistre64):

( t , P) (.3 , .7) -(0 , 0 ) ------- .3 , .7 ; slope = P/t = .7/.3 = 7/3

OpenStudy (amistre64):

correct

OpenStudy (anonymous):

I am confused with what you wrote previously D:

OpenStudy (amistre64):

ugh ... i cant type to save my life today

OpenStudy (amistre64):

what is the (t,P) at t=0?

OpenStudy (anonymous):

sorry D; it will be (0.0s, 0cm)

OpenStudy (amistre64):

good, now: what is the (t,P) at t=.3?

OpenStudy (anonymous):

(0.30s, 75 cm)

OpenStudy (amistre64):

good, now lets use those to find the slope between them: |dw:1320512622663:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!