How do i find the slope of these data?
Time (s) 0.0 0.10 0.20 0.30 0.40 0.50 0.60 Position (cm[W]) 0 25 50 75 75 75 0
I tried this: (0.60, 0.0)(0.50, 75 cm) m = 0.0 - 75 cm ----------- 0.60s - 0.50s = -75 cm -------- 0.1s = -750 cm/s
slope between any 2 points (a1,a2) and (b1,b2) is simply the ratio of the differences between them: \[\frac{a2-b2}{a1-b1}\]
yup, it is. But somehow I feel like my answer is wrong.
no, its good; the math dont lie
at that end its a negative slope since it goes from high to low
also, if I want to find the slope from 0.0s - 0.30s how can I put the coordinates together/
same way; the formula for slope doesnt change simply becasue the number change
also
\[\frac{change.in.position}{change.in.time}\]
I tried to find the slope from 0.0 s - 0.30s, and I did this: (0.30s, 0.0s)(0.30s, 75 cm) m = 75 - 0.0 ------- 0.30 - 0.30 = n/a
time changes from 0.0 to 0.3; not from 0.3 to 0.3
.3-0 = .3 for your denominator
I tried the y2-y1/x2-x1
and if I plot (0.30, 0.0) (0.30, 75)
you tried yes; but you simply inserted the numbers wrong. keep an eye on that :)
your first plot is (0,0) NOT .. (.3,.3)
well, i typoed that up dint i
ohhh, noo D;
your first plot is (0,0) NOT .. (.3,0) thats better lol
why will my first plot be (0,0)
at time = 0, what is your position?
"if I want to find the slope from 0.0s - 0.30s how can I put the coordinates together" what is the (t,P) at 0? what is the (t,P) at .3?
ohhh...
so the t = 0.0s and position is 0 cm t - 0.30s and position is 75 cm
( t , P) (.3 , .7) -(0 , 0 ) ------- .3 , .7 ; slope = P/t = .7/.3 = 7/3
correct
I am confused with what you wrote previously D:
ugh ... i cant type to save my life today
what is the (t,P) at t=0?
sorry D; it will be (0.0s, 0cm)
good, now: what is the (t,P) at t=.3?
(0.30s, 75 cm)
good, now lets use those to find the slope between them: |dw:1320512622663:dw|
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