Find the domain for 2x^2+7x-5, which is the denominator for a certain fraction.... I did the quadratic formula, and got a weird answer.... can someone please help me?
what did you get when you used the quadratic formula?
hold on, let me find my notes.There's stuff all over my room, I am remodeling, and its somewhere...
-7+/-sqrt(89)/4
I'm assuming everything is over 4 If so, then you have the correct answer.
Those are the zeros. They make the entire polynomial equal to zero.
So you have to exclude them from the domain
how would you put that into the form (a,b)?
You can either enter them as they are or you can approximate them So if you use the exact answers, then the domain is \[ \left(-\infty, \frac{-7-\sqrt{89}}{4}\right)\cup\left(\frac{-7-\sqrt{89}}{4}, \frac{-7+\sqrt{89}}{4}\right)\cup\left(\frac{-7+\sqrt{89}}{4}, \infty\right)\] but that is really really messy.... so I'd go with the approximate zeros The two zeros are approximately -4.108495283 and 0.6084952830 This means we have to exclude these values from the domain So the domain is \[ \left(-\infty, -4.108495283\right)\cup\left(-4.108495283, 0.6084952830\right)\cup\left(0.6084952830, \infty\right)\]
can you put that in fractional form, please?
the first answer is in fractional form
but you can't represent the answer in the form a/b where a and b are integers
okay
how about rounding it?
to the nearest thousandth, the domain is \[ \left(-\infty, -4.108\right)\cup\left(-4.108, 0.608\right)\cup\left(0.608, \infty\right)\]
I thought the domain for this one was all real numbers.
not if that polynomial is the denominator of some fraction
oh.
yeah that was my initial thought too
hopefully the domain of the numerator is all real numbers
true...
but I'm assuming that the numerator is some polynomial too
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