domain of the function
f(x)=3vx^2-x+1
it means cube root of x^2-x+1 domain of the function
f(x)=3vx^2-x+1
it means cube root of x^2-x+1 @Mathematics

Question

domain of the function 
f(x)=3vx^2-x+1 
it means cube root of x^2-x+1 domain of the function 
f(x)=3vx^2-x+1 
it means cube root of x^2-x+1 @Mathematics

jim_thompson5910 · Answer

Since you can take the cube root of any number, the domain is the set of all real numbers.

anonymous · Answer

how can i solve it out pls? my proff is very strict in marking

jim_thompson5910 · Answer

there's not much to solve


the cube root of any number is always defined


also, the domain of any polynomial is the set of all real numbers, so this means that the radicand will always be defined.


So this means that no matter what value of x you plug in, you'll always get some number as a result.

anonymous · Answer

which means -infinity to infinity?

jim_thompson5910 · Answer

yep, the domain is $$\Large \left(-\infty,\infty\right)$$