Question

(cosx/(secx-tanx)) = 1+senx
i dont know how to prove this! HELP

Answer 1

I got this. Give me a sec

Answer 2

thanks

Answer 3

\[\cos(x)/(\sec(x) - \tan(x))\]\[(\cos(x)/(\sec(x) - \tan(x))) * (\sec(x) + \tan(x)/(\sec(x) + \tan(x)))\]\[(\sec(x) + \tan(x)) * (\cos(x)/\sec^2(x) - \tan^2(x))\]\[(\sec(x) + \tan(x)) * \cos(x)/1\]\[\sec(x)*\cos(x) + \tan(x)*\cos(x)\]\[1 + \sin(x)\]

Answer 4

That's ugly... I wish I knew better formatting tools

Answer 5

cosx /(secx-tanx)
= cos x / ( 1/cosx - sinx / cosx)
=cosx / (1-sinx)/cosx)
= cos^2x / 1-sinx
= 1-sin^2x/1-sinx
= (1+sinx)(1-sinx)/(1-sinx)
=1+sinx

Answer 6

thank you so much