Question

How do I determine the acceleration at 1.0s, 3.0s, and 5.5s?

Answer 1

Velocity at 1.0s is 7.5 m/s [W]
at 3.0s is 15.0 m/s [W]
at 5.5s is 7.5 m/s [W]

Answer 2

I tried to do slope

a = Vf-Vi
-----
delta time

= 0-7.5cm/s
-----
1s
= -7.5 cm

but the answer is 7.5 m/s^2 [W] D:

Answer 3

acceleration =\[\Delta v / \Delta t\]
(7.5 m/s - 0) / (1s - 0) = 7.5 m/s^2

Answer 4

do I make my acceleration = 7.5 m/s [W] - 0 / 1s = 7.5 m/s^2 [W]?

Answer 5

because then I find the correct answer.. o.o

Answer 6

(7.5 m/s - 0) / (1s - 0) = 7.5 m/s^2
(15 m/s - 7.5) / (3s - 1) = ? m/s^2
(7.5 m/s - 15) / (5.5s - 3) = ? m/s^2

Answer 7

You need to make sure you get your initial and final velocities correctly placed in the formula...once you do that these are pretty easy

Answer 8

ohh, yup I made a mistake when I put my initial and final velocities >_<"

Answer 9

:)

Answer 10

but oh, for the velocity at 5.5s is 7.5 m/s [W], it asks for its acceleration:

a = Vf-Vi
-----
delta t
= 0 - (-7.5 m/s [W])
----------------
0.5s
= 7.5 m/s [W]
-----------
0.5s
= 15 m/s^2 [E]

Answer 11

and 15 m/s^2 [E] is the correct answer, but I'm wondering why it is east and not west..

Answer 12

Think about it: you were going 15/ms W and went down to 7.5 m/s...you had to have a negative acceleration...which would be in the opposite direction

Answer 13

ohhhh!!!