Question

Determine the quadratic function f(x) = ax^2+bx+c, whose vertex is (-2, -11) and passes through the point (-5, 7). Please show all of your work. @Calculus1

Answer 1

listen make factors into (x+2) and (x+5), because at these points of x equation would be valid and posses a certain value of y, so then multiply these factors to get the answer

Answer 2

and after making equation if u put these value of x that is -2,-5, then it should the y as(-11,7)

Answer 3

medals needed :P

Answer 4

hoose the least common multiple of 12 and 24.
A. 6
B. 12
C. 24
D. 36

Answer 5

(x+2)^2 -(1/2)(y+11)=0 eq of parabola

Answer 6

how did you get this answer Mark O. ??

Answer 7

can you please show the work..thanks

Answer 8

vertex is (-2, -11)
use,
4a(y--11)=(x--2)^2
4a(y+11)=(x+2)^2,passes through the point (-5, 7).
4a(7+11)=(-5+2)^2
4a(18)=(-3)^2
72a=9
a=9/72=1/8, therefore
4(1/8)(y+11)=(x+2)^2
(1/2)(y+11)=(x+2)^2
(x+2)^2 -(1/2)(y+11)=0 eq of parabola

Answer 9

ask me if you have question

Answer 10

thank you mark o.
I really appreciate it. :)