Question

Given the function f(x) = -x^2-6x-2
i. Determine the vertex;
ii. List the axis of symmetry;
iii. Calculate the y-intercept;
iv. Use the axis of symmetry and the y-intercept to find an additional point on the graph;
v. Graph the function

Please show all of your work. Given the function f(x) = -x^2-6x-2
i. Determine the vertex;
ii. List the axis of symmetry;
iii. Calculate the y-intercept;
iv. Use the axis of symmetry and the y-intercept to find an additional point on the graph;
v. Graph the function

Please show all of your work. @Mathematics

Answer 1

f(x) = -x^2-6x-2 the negative sign in x might tells us that the parabola opens downward
vertex x=-b/2a
x=-(-6)/2(-1)=6/-2=-3 sub this to f(x) gives
f(3)= -(-3)^2-6(-3)-2=-9+18-2=7 therefore
vertex(h,k)=(-3,7) ans
110 axis of sym is at y

Answer 2

11) axis of sym is at y

Answer 3

f(x) = -x^2-6x-2 when x =0, y=f(0)=-2 ,,,y intercept

Answer 4

y=f(x) = -x^2-6x-2 when y=0, we can solve for the x intercepts, by using the formula
x=[-b-+sqrt(b^2 -4ac)]/2a a=-1,b=-6 and c=-2 we get
x=-0.354,-5.6

Answer 5

to graph this use these points x=-0.354,-5.6, x =0, y=f(0)=-2 ,,,y intercept

Answer 6

also use the points of the vertex x=-3, y=7