Question

The derivative of the inverse function of \(x^5 + 3 x^3 + 7 x + 2\) at the point (13,1) is?

Answer 1

y = x^5 + 3x^3 + 7x + 2

We want dx/dy at the point (1, 13)

y' = 5x^4 + 9x^2 + 7

thus dx/dy = 1/(5x^4 + 9x^2 + 7)

at the point x = 1, dx/dy = 1/21

= 1/21