Question

lim [(x^2+3x-1)tanx]/(x^2+2x) . x->0

Answer 1

= (1 + 3/x - 1/x^2)tanx/(1 + 2/x)

= (1 + 0 - 0)*0/(1 + 0)
= 0

Answer 2

Answer is supposed to be -0,5

Answer 3

note that \[\lim_{x\to 0}\frac{\tan(x)}{x}=1\]

Answer 4

see the attachment ^

Answer 5

First step I multiplied and divided everything by "x" so that I get the limit which Zarkon here said ;)

Answer 6

Thanks!

Answer 7

You're welcome :)

Answer 8

damn. where did i go wrong? i can't see it

Answer 9

You have a division by zero there, check the 1+2/x

Answer 10

oh wait, i'm a complete idiot. i evaluated the limit of 2/x to be 0...