Question

4. In the figure below two congruent squares touch at one corner. One side of the square measures 5 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure 4. In the figure below two congruent squares touch at one corner. One side of the square measures 5 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure @Mathematics

Answer 1

62.5 cm^2

Answer 2

62.5

Answer 3

how did u guys get that? -confused-

Answer 4

Area of two squares = 50cm^2 (25 + 25)
Area of triangle = (1/2) *base * height
(1/2) * 5*5 = 12.5 cm^2
and you need not mention to find the area to nearest tenth, because it comes only in one decimal.

Answer 5

so how did you get 65.2?

Answer 6

It's 62.5

Answer 7

it is 62.5

Answer 8

And even you can take the area of triangle to be half of the area of square

Answer 9

sorry 62.5... i still dont understand ur equation says 12.5

Answer 10

Area of triangle = (1/2) * base * height
That is equal to 25/2 which is 12.5

Answer 11

so where does the 62.5 come in :'( im so sorry i dont ubderstand

Answer 12

area of sq is 50cm^2 and area of triangle is 12.5
So whole area is 50+12.5 =62.5

Answer 13

omg i feel so stupid than k uu

Answer 14

It's good to clear doubts

Answer 15

thank u

Answer 16

Your are always welcome..