Question

I have a question, I will type it out using the equation feature, so wait a sec when you look at this :)

Answer 1

sorry im lagging...almost done

Answer 2

just a sec, ill try again, the bloody thing wont load

Answer 3

\[\sqrt{18x}/4 +\sqrt{2x/4}\] No division, theyre fractions

Answer 4

yes

Answer 5

add radicals

Answer 6

3 root of x

Answer 7

\[3x^{1/2}\]

Answer 8

sqrt 18x =3 sqrt2x
\[\frac{3\sqrt{2x}}{2} + \frac{\sqrt{2x}}{2}\]
\[=\frac{4\sqrt{2x}}{2}\]
\[=2\sqrt{2x}\]

Answer 9

so is that the final answer? the bottom

Answer 10

(root of 18 * root of 2) * root of x
root of 36 * root of x
(6*root of x)/2
3 root of x

Answer 11

Oh yes, I made a mistake with multiplication

Answer 12

Sorry, regret my answer

Answer 13

ok thanks Diya :) I will look over this and try more problems out ^_^

Answer 14

are you sure? it said it was wrong

Answer 15

\[2\sqrt{2x}\]

Answer 16

no the top was \[5\sqrt{2x}\]

Answer 17

the math thing checked it, then gave me a new problem >.<

Answer 18

If the problem is
\[ \frac{\sqrt{18x}}{4} +\sqrt{\frac{2x} {4}}\]
then you would get
\[ \frac{3\sqrt{2}}{4}+\frac{\sqrt{2x}}{2} \]
\[ = \frac{3\sqrt{2}}{4}+\frac{2\sqrt{2x}}{4}=\frac{5\sqrt{2x}}{4} \]