What are the solutions for x in the proportion 4x-3 = 2x ---- ---- x 2 What are the solutions for x in the proportion 4x-3 = 2x ---- ---- x 2 @Mathematics
cross multiply: 8x-6 = 2x^2 subtract 8x add 6 0=2x^2 -8x +6 can you do it from there?
What are the solutions for x in the proportion 5x-6 = 2x ---- ---- x 2
Factor out 2 0 = 2(x^2 -4x +3)
now we can look at it. in order for that to be correct the right side needs to equal 0 well in order for the right side to be zero whats in side the ( ) needs to equal zero
ive bet youve found the zeros of an equation like the one in the ( ) before =)
Write a radical expression that has 4 terms (without variables), that are not in simplest form. Create this expression so that, once the terms are in simplest form, they can be combined to make an expression with one or two terms.
do you know what a radical is?
Nope.. Just need the answer to the question that.. it would be most helpful
ill help you answer it if ya want. i try not to do peoples homework for them tho
I understand.. but it would be quick and easier to just give the answer.. That's All
yes yes it would.. but you wouldnt learn anything
True.. Ok sbut get straight to the point. nothing extra
ok so a radical is the name of a square rt sign.. \[\sqrt{}\] that thing
so a radical expression is just numbers with that sign
Do you know what a term is?
I understand the radical sign and terms i just need to know how to solve this
so basically what they want is ??? + ????+ ???? +???
there needs to be a radical sign in it
and each term needs to be more than just 1 number
an example of this would be Sqrt(9)+ 2*3 + sqrt(25) - 3*1
Could i use this example in this situation?
no cause i did that one.. try and do your own
Ok I got it.. but i have another Math Question
What is the exact value of the expression \[5\sqrt{5}^+3 \sqrt{20}^-6\sqrt{3}\]
ok so here we want to look at the \[3\sqrt{20}\]
\[3\sqrt{20} \] also equals \[3\sqrt{5 * 4}\] which equals \[3\sqrt{5}\sqrt{4}\]
and you know what the sqrt of 4 is
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