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differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
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does this really say \[2^{\sin(\pi)x}\]?
\[2^{\sin(\pi x)}\] perpaps
or is it \[2^{\sin(\pi x)}\]
flip the pi and x
if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]
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oh wait . you got it right. my basd vison
ok got it. thanks
yw
hello myininaya!
satellite i need your help
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i see you in chat
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