Question

im stuck here, please solve for t.

Answer 1

t = 1.45126

Answer 2

\[(10/11)=(75/110)^(t/30)\]

Answer 3

how did you get that math mind? i hadnt even posted the equation

Answer 4

it looks like you raised one of your parenthesis
does that mean t/30) should also be raised?

Answer 5

oops. im retyping.yes myininaya

Answer 6

t=440

Answer 7

\[(10/11)=(75/110)^(t/30)\]

Answer 8

what the heck it doesnt do it.

Answer 9

lmfao, thanks for the medal.... you gotta type into { }

Answer 10

\[\frac{10}{11}=(\frac{75}{110})^{\frac{t}{30}}\]
take natural log of both sides
so then we can write
\[\ln(\frac{10}{11})=\frac{t}{30} \ln(\frac{75}{110})\]

Answer 11

im gona check your answer karate

Answer 12

doesnt there have to be an e to bring down the t/30

Answer 13

k i just tried it i didnt really understand what myin was saying about raised so i may have it wrong

Answer 14

yup karate. your wrong.

Answer 15

remember: \[\ln(x^r)=r \ln(x)\]

\[30 \cdot \ln(\frac{10}{11}) \cdot \frac{1}{\ln(\frac{75}{110})}=t\]

Answer 16

i thought so.... wtheck myin???? what math level is this?!?!?!?!

Answer 17

ok myiniaya im working on getting your resulsts with your intial setup

Answer 18

t is approx=7.465700356

Answer 19

i get 30 times( ln10/11over ln75/110)

Answer 20

i dont have a calculator

Answer 21

samething

Answer 22

alrie thanks

Answer 23

do you what a medal?

Answer 24

\[30 \cdot \ln(\frac{10}{11}) \cdot \frac{1}{\ln(\frac{75}{110})}= 30 \cdot \frac{\ln(\frac{10}{11})}{\ln(\frac{75}{110})}\]

Answer 25

you can also write this a couple of other different ways

Answer 26

yup i got that. :)

Answer 27

your awsome dude god bless

Answer 28

using our properties of log

Answer 29

i prefer to be called a dudette thanks

Answer 30

lol myin and i r girls!

Answer 31

thanks sista form anotha mista. :)

Answer 32

thats goofy but i accept lol

Answer 33

coo

Answer 34

hahahahahahahahahahaha! but i come from a mother not a father. i dont think males get pregnant....hmmmjk!