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Find the domain of the function: (will input the function when I can use the equation box, lol.) Find the domain of the function: (will input the function when I can use the equation box, lol.) @Mathematics
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\[f(x) = \frac{3+x}{\sqrt{3x^2+2x-5}}\]
3x^2 +2x -5=0 3x^2+5x-3x-5=0 x(3x+5)-1(3x+5)=0 (x-1)(3x+5) x=1,x=-5/3 Domain=R-{1,-5/3}
so can it be -5/3? I thought if it's a - under the sqrt symbol it's not possible.
So domain is x >1 or x < -5/3
D={x| x > 1 or x<-5/3} or should I state: \[(-\infty,\frac{-5}{3})\cup(1,\infty)\]
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(−∞,−5/3)∪(1,∞) is the domain.
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