Question

help please x^2+2x+1-Q^2=

Answer 1

If Q is a numeric constant, you can solve the equation with the quadratic formula but setting

a = 1
b = 2
c = +1-q^2

Of course the delta won't give you a perfect root, and you'll have some solutions where this Q appears everywhere.

Answer 2

thnks :O)

Answer 3

Or, another way you could do it, is applying the following:

(a+b)^2 = a^2+2ab+b^2

So...

(x+1)^2 - Q^2

Now.

\[a^2 - b^2 = (a+b)(a-b)\]

So

\[(x+1-Q)(x+1+Q)\] = 0

Zero product property and...

x = Q-1
x = -1-Q

Answer 4

that makes it much easier thank you!

Answer 5

You're welcome!