|r+2|<6
|r+2|<6 break up the inequality like so: -6<r+2<6 subtract 2 from each section of the inequality: -8<r<4
|r+2|<6 r + 2 < 6 - 2 -2 r < 4 |r+2|<6 r + 2 > -6 -2 -2 r > -8 -8 < r < 4
\[-1<x-1\le3\]\[\left| ? \right|\]
absolute value of question mark? I don'n know the meaning of this
−1<x−1≤3 0<x≤4
- 1 < x - 1 ≤ 3 +1 +1 +1 0 < x ≤ 4
thats one of my choices ......thanks
\[x \le1 or x \ge-3\]
what do you need to do with this?
solve the inequality and give the solution in interval notation
it's already solved so the interval notation is just\[x \le 1\rightarrow(-\infty,1]\]\[x \ge -3\rightarrow[-3,\infty)\]so the answer is written as \[(-\infty,1]\cup[-3,\infty)\]
sorry wrong one.....find the solution set for the inequality
oh I see you just want the intersection.. so that would be where \[(-\infty,1]\]and \[[-3,\infty)\] overlap, that is \[[-3,1]\]
is that a choice?
|8m+2|+5>9
first subtract 5 from both sides. tell me what you get.
3m+2+5>14
no I just said subtract 5 from each side. that is |8m+2|+5>9 -5 -5 ------------ ??????????????
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