Question

Reduce: (32 x^7 y^5 z^9 a^2)^(1/3)

I got: (4z^3 x^2 y)(a^2 xy)^(1/3) as my answer. Am I wrong?

Answer 1

\[\sqrt[3]{{32}x ^{7}y ^{5}z ^{9}a ^{2}}\]

Answer 2

Thats a cubed root btw.

Answer 3

\[4z ^{3}x ^{2}y \sqrt[3]{a ^{2}xy}\] is what i got for my answer

Answer 4

4 not can be because 4*4*4=64

Answer 5

cuberoot32 = 2cuberoot4

Answer 6

x7 =xcuberootx4

Answer 7

Ah yeah I see what I did wrong

Answer 8

y5=ycuberooty2

Answer 9

z9=z2cuberootz

Answer 10

a2 reamind inside in this form

Answer 11

but the cuberoot of z^9 is z^3 isnt it?

Answer 12

z^3 x z^3 x z^3 = z^9

Answer 13

not is because this is cuberoot not squareroot

Answer 14

no what you have wr

Answer 15

e is x27

Answer 16

sorry z27

Answer 17

right ?

Answer 18

but when you multuply you add the exponents

Answer 19

you dont multiply the exponents

Answer 20

when you have exponent of exponent you need multiply exponentes

Answer 21

how cuberoot8 =2

Answer 22

is 2*2*2

Answer 23

so

Answer 24

2 x 2 x 2 = 8 z x z x z x z x z x z x z x z x z = z^9

Answer 25

2^3 = 8 (z^3)^3 = z^9

Answer 26

yes but z9 =(z3)3 = z3*z3*z3 =z27

Answer 27

No you dont multiply exponents, you add them

Answer 28

you just said z^9 = z^27 in your statement lol

Answer 29

so but there is cuberootz9

Answer 30

z9=z3*z3*z3
cuberootz3=z so cuberootz9=z*z*z=z3

Answer 31

Yeah that's what I said

Answer 32

ok now is right ALL ?

Answer 33

Yeah, just remember when you multiply, you add the exponents, and when you divide, you subtract the exponents.

Answer 34

can solve now your exercise ?

Answer 35

Yeah I did, the problem with my original answer was the 4 on the outside. Should have been a 2 on the outside and left a 4 inside the squareroot

Answer 36

cuberoot

Answer 37

Yeah thats what I meant my bad

Answer 38

ok bye

Answer 39

Thanks :)

Answer 40

my pleasure

Answer 41

good luck