Question

Solve lim (x^3-3x^2+1) / (x^5-x^4+2x^3-5) . x-> infinity .

Answer 1

limit = 0

Answer 2

\[\lim_{x \rightarrow \infty} {(x^3-3x^2+1) \over (x^5-x^4+2x^3-5)} =0\].

Answer 3

want shown work?

Answer 4

Did you divide everything by x^5?

Answer 5

yup, do you see how that leads to the limit being zero?

Answer 6

L'hopital's rule over and over until you get 6 in the numerator and a polynomial in the denominator

Answer 7

0

Answer 8

I prefer the dividing top and bottom by x^5, its obvious at a glace that way

Answer 9

Yes , thanks .