Question

e figure given below shows the path of a steel ball of mass 0.500kg after being thrown from the point P with a speed of 28.0m/s .
Calculate the speed of the ball at Q.

an hour agoReport Abuse

Alisha22 0
an hour agoReport Abuse
1 attachments
p1060930.jpg @Physics

Answer 1

how do u view the attachment?

Answer 2

sori

Answer 3

Its ok. at the top of a parabolic flight path, the speed is simply the magnitude of the velocity in the horizontal, or x-direction, ONLY! So, it would be \[v_Q =28*\cos(\theta)\] for whatever ur angle theta is

Answer 4

theta isnt given

Answer 5

Ok u will have to find theta. Do u want me to solve for theta and just tell u? or show u how?

Answer 6

Ok i figured it out, it took me a minute...

Answer 7

20.277 m/s is the answer

Answer 8

I can help you out if you're still having trouble and don't understand how the problem works. =D