Question

lim of (1 + 7^(n)) / 9^(n) as n ----> oo

Answer 1

\[\frac{1}{9^n}+(\frac{7}{9})^n\]

Answer 2

7/9 is a fraction between 0 and 1 so it goes to 0

same with the 1/9 .....

Answer 3

it goes to zero because its a fraction?

Answer 4

well, becasue its a fraction whose absolute value is between 0 and 1

Answer 5

at large n we get:

\[\frac{1}{100000000000000}+\frac{puny}{100000000000000}\]
which are pretty small

Answer 6

ahh the way I see it is that the denominator is bigger than the numerator so the fraction will get smaller as n increases. is that correct?

Answer 7

thats correct

Answer 8

cool. thanks man. I might be posting another question soon lol

Answer 9

good luck :)