Question

Rationalize the denominator. Assume the variable is positive. PLEASE HELP!

Answer 1

\[7/\sqrt[3]{98y}\]

Answer 2

\[\frac{7}{\sqrt[3]{98y}} = \frac{7}{98y ^{2/3}}\]

Is this what you mean be rationalised? No square root symbol in the denominator?
Remember that you can now bring it to the numerator by the rule:

A^(-n) = 1/a^n

Answer 3

Oh, my bad. This should be
7/98y^(1/3) rather than (2/3). My mistake.

Answer 4

...?

Answer 5

\[\sqrt{x}= \sqrt[2]{x}=x ^{1/2}\]

When you have:
\[\sqrt[3]{98y}=98y ^{1/3}\]

Does this make sense?

Answer 6

it's not correct. :/

Answer 7

What is the answer? Is the answer:
\[7\times98y ^{-\frac{1}{3}}\]

Answer 8

7/(98y)^(1/3) = 7*(98)^(2/3)/98y

= (98)^(2/3)/14y