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Mathematics 15 Online
OpenStudy (anonymous):

evaluate the following : evaluate the following : @Mathematics

OpenStudy (anonymous):

\[\int\limits_{}^{}e ^{x}\cos x(1-\cot x).dx\]

OpenStudy (anonymous):

try trigonometric substitution!

OpenStudy (anonymous):

how???

OpenStudy (anonymous):

how did they proceeded i need the steps plssssssssssssss

OpenStudy (anonymous):

I have no idea how they proceeded. I'm only at the level of calculus 2!

OpenStudy (anonymous):

wait a minute e^x( cosx - cosx*cotx) Hmm... e^x*cosx - e^x*cos^2x/sin x hey just try by parts, just do it I am sure things will get simple

OpenStudy (anonymous):

cot x's derivative is coesc^2x, right?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

@ishaan: i tried it out but it didn't work!!!

OpenStudy (jamesj):

Now integrate the two function separately. To integrate e^x cos x, integrate by parts twice. I.e., let \( J =\int e^x \cos x dx \). Then \[ J = e^x \sin x - \int e^x \sin x \ dx \] \[ = e^x \sin x - \left( - e^x \cos x + \int e^x \cos x \ dx \right) \] \[ = e^x (\sin x + \cos x) - J\] and therefore \[ J = \frac{1}{2} e^x (\sin x + \cos x) \]

OpenStudy (anonymous):

what about e^x*cosx*cotx?

OpenStudy (anonymous):

@James: what about the other part of the question???

OpenStudy (jamesj):

are you sure it's cot x, not tan x?

OpenStudy (anonymous):

ya it is!!!

OpenStudy (anonymous):

Yeah wish it was tan x

OpenStudy (jamesj):

because it's very ugly and there's no elegant solution; or rather, no expression in terms of elementary functions, as the Wolfram solution demonstrates.

OpenStudy (anonymous):

k!!!!

OpenStudy (anonymous):

thanks guyz

OpenStudy (anonymous):

DASHINI chck your question again

OpenStudy (anonymous):

i am damn sure about the question

OpenStudy (anonymous):

it ok i'll better ask my teacher if possible

OpenStudy (anonymous):

The other integral you posted all is tough, it requires quite alot of work.

OpenStudy (anonymous):

they won't give you the question, if it's beyond you

OpenStudy (anonymous):

thats better tanks

OpenStudy (anonymous):

there must be a way, keep looking for it... I will see if I can get through this

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