Question

Match each system of linear equations with the quadrant in which the solution lies.
Answer

two y plus sixteen equals negative three x...y minus one forth x equals five
Read Answer Items for Question 14

Y minus fifty equals ten x...y minus x equals two
Read Answer Items for Question 14

Five y plus one equals two x...negative two y equals x minus fourteen
Read Answer Items for Question 14

Y plus three x equals eight...seventeen plus y equals five x
Read Answer Items for Question 14

Answer
A.
Two
B.
Four
C.
Three
D.
One
Match each system of linear equations with the quadrant in which the solution lies.
Answer

two y plus sixteen equals negative three x...y minus one forth x equals five
Read Answer Items for Question 14

Y minus fifty equals ten x...y minus x equals two
Read Answer Items for Question 14

Five y plus one equals two x...negative two y equals x minus fourteen
Read Answer Items for Question 14

Y plus three x equals eight...seventeen plus y equals five x
Read Answer Items for Question 14

Answer
A.
Two
B.
Four
C.
Three
D.
One
@Mathematics

Answer 1

please help me!

Answer 2

the answers are the different quadrants if that helps any

Answer 3

y+16=-3x
y-x/4=5--->y=x/4+5

x/4+5+16=-3x
13x/4=-21
x=-84/13
y=-21/13+5=44/13
this is in the second quadrant

Answer 4

because we have a positive y and negative x...the others work the same way, but I may not have time to finish, I'm leaving soon.

Answer 5

in general if the solution to a system has
y>0 and x>0 we are in quadrant 1
y>0 and x<0 we are in 2
y<0 and x<0 we are in 3
y<0 and x>0 we are in 4

Answer 6

next one:
y-50=10x
y-x=2--->y=x+2

x+2-50=10x
9x=-48
x=-48/6<0
y=-48/6+12/6=-6<0
so since y<0 and x<0 we are in quadrant 3

Answer 7

i just dont understand how to take an equation and put it to a graph. Do you get what im saying?

Answer 8

you cannot graph y=x?

Answer 9

can you graph any equation? or are you completely lost in that department?

Answer 10

this is my first time ever seeing this sort of stuff

Answer 11

so yea sorta completely lost

see i am previewing a pretest that leads into the lessons for this stuff.

Answer 12

well if you know practically nothing of graphing I don't know why you are solving solution sets, that is more advanced than just graphing y=x
I will try to give the idea briefly:
to graph a linear function we need to find two points and draw a straight line. to find our points use the equation and try various values of x:
let's use the example

y=2x+1
if
x=0
then
y=2(0)+1=1

so the point (0,1) is on our graph

if
x=1
y=2(1)+1=5

so (1,5) is another point. do you know how to plot these points on a graph?

Answer 13

oo ok yea i know how to plot. and thanks i understand it now

Answer 14

just because I had almost finished the drawing anyway, here it is (for the example I created)