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Factor completely
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\[m^3n-8m^2n^2+12mn^3\]
there is m2n and m2n2 and mn2 ?
the 1st is m^3n and then 2nd one is correct and 3rd is mn^3
ok
m3n -8m2n2 +12mn3 yes ?
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yes that is correct.
mn(m2 -8mn +12n2)
so than m2-8mn +12n2 =(m-2n)(m-6n)
than this all will be mn(m-2n)(m-6n)
ok ?
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do you understand it ?
sorta but not really sorry im terrible at math :/
what is not clearly ?
what is the first step
first you see that mn is the common term in every terms so than this can be extracting than you get mn(....)
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ok ?
and after this inside parantheses you have m2-8mn+12n2 so here you need get two numbers a and b so than a+b =-8 and a*b=12
a+b=-8 so -6-2=-8 and -6*-2=12
right ?
now is clearly ?
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