At an interest rate of 4% compounded annually, how long will it take to double the following investments? (Round your answer to the nearest year.)
(a) $100
_____ years
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OpenStudy (anonymous):
why is it not 25?
OpenStudy (anonymous):
200 = 100(1 + 0.4)^n
solve for n
OpenStudy (anonymous):
wait isnt n 1
OpenStudy (anonymous):
(1.04)^n = 2
n ln 1.04 = ln 2
n = ln 2/ ln 1.04 = 17.67
18 years
OpenStudy (anonymous):
why does 1.04^n = 2?
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OpenStudy (anonymous):
(1.04)^n = 200/100
OpenStudy (anonymous):
i dont get what u did after that. could u retricewords to explain ur steps?
OpenStudy (anonymous):
retrice? i said USE
OpenStudy (anonymous):
have you seen the formula before
ie amount = principap ( 1+ annual rate) ^ number of years
A = P(1 + r)^n
OpenStudy (anonymous):
yes i have
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OpenStudy (anonymous):
u get 2=1.04^n and then what
OpenStudy (anonymous):
how do u get 18?
OpenStudy (anonymous):
(1.04)^n = 2
when the unknown is the exponent you then take logarithms (logs) of both sides
do you know about logs?
OpenStudy (anonymous):
sorry i have to go out for a while marion - maybe we can talk later
OpenStudy (anonymous):
not really no.
and thta's fine. the name is mario by the way.
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