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Mathematics 20 Online
OpenStudy (anonymous):

can someone explain what this question is asking..please and thank you! @Physics

OpenStudy (anonymous):

The original pendulum is taken to the moon and released from rest at a position 0.25 meter above its lowest point. Compared to the period of the pendulum on Earth, the period of the pendulum on the moon is (1) shorter (2) longer (3) the same

OpenStudy (anonymous):

the original pendulum was 0.65-meter-long simple pendulum consists of a 1.0-kilogram massat the end of a string. The pendulum is released from rest at position A,o.25 meter above its lowest point.

OpenStudy (turingtest):

Remember our equation:\[ T=2\pi \sqrt{l \over g}\]If we take this pendulum to the moon which of these variables changes?

OpenStudy (anonymous):

the g right..?

OpenStudy (turingtest):

right, does it's value go up or down when we take it to the moon?

OpenStudy (anonymous):

down b.c i think it is 1.62 m/s^2 (not sure)

OpenStudy (turingtest):

I have no idea what gravity is on the moon, but the point is that it goes down. So if g goes down, what happens to T?

OpenStudy (anonymous):

increases

OpenStudy (turingtest):

Bingo! a medal for you :)

OpenStudy (anonymous):

thnx lol

OpenStudy (turingtest):

note that if g=0 (like in outer space) then T=infinity which makes sense because a pendulum would not swing without grabity, it would just float there. Cool huh? and they say science is boring... psh...

OpenStudy (anonymous):

lmao its cuz they dont know anything about it lol

OpenStudy (anonymous):

wat is the answer? longer?

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