h(t)=-16t^2+voT+ho. Initial velocity is 64ft/s. The rocket hits the ground in 4 seconds. If the rocket reached its maximum height (vertex) t=2 seconds, what is the value of maximum height?

Question

hero · Answer

I'm pretty sure the initial height is zero, so you don't even count it

hero · Answer

4 = -16t^2+64t

Now we just solve for t

hero · Answer

-16t^2+64t - 4 = 0

anonymous · Answer

-32t^2-256t-16

anonymous · Answer

never mind..im suppose to factor right?

hero · Answer

-4(4t^2-16t+1) = 0
4t^2-16+1 = 0

anonymous · Answer

is it 96 feet?

hero · Answer

4t^2+(-8 + 2sqrt{15})x + (-8 - 2sqrt{15})x + 1 = 0

anonymous · Answer

confused...

anonymous · Answer

ok

hero · Answer

Belay that

anonymous · Answer

Can you take a look at this Hero when you get a chance. Thanks http://openstudy.com/?F47433677217634HJ3W=_#/updates/4eb9de7ce4b0fc85a8ca99ac

hero · Answer

http://www4c.wolframalpha.com/Calculate/MSP/MSP107919i1bb1bac4a2a8a000060bbb7722ec2662e?MSPStoreType=image/gif&s=6&w=362&h=655

anonymous · Answer

belay?

anonymous · Answer

okay I got it..thanks

anonymous · Answer

tht was a complicated problem..thanx for helping