Question

A small planet has a spherical shape, its radius is 20 km, it is covered with ice whose thickness is 1/4 km (250 m). use differentials to approximate the volume of the ice.
Please show a detailed solution, @Calculus1

Answer 1

Dy=F'( x)(Dx)
\[F'(x)=4\pi r^2\]
Dx=1/4
\[Dy=4*\pi*20^2*.25--->1256km\] That's the volume of the Ice

Answer 2

You have to take the derivative of the volume