Input the equation of the given line.The line including (2, 3) and (2, 5) Input the equation of the given line.The line including (2, 3) and (2, 5) @Mathematics
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jimthompson5910 (jim_thompson5910):
The x coordinates are the same and equal to 2.
So the equation of the line is x = 2, and this is a vertical line that cuts through 2 on the x axis
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
y=2x+
jimthompson5910 (jim_thompson5910):
no it's simply x = 2 and no y terms are involved
OpenStudy (anonymous):
Ok thanks can you help with another
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OpenStudy (anonymous):
Input the equation of the given line in standard form.The line including (3, 1) and (-2, 3).
jimthompson5910 (jim_thompson5910):
step 1 is to find the slope, how do we do that?
OpenStudy (anonymous):
y1-y2
x1-x2
jimthompson5910 (jim_thompson5910):
good, so subtract the corresponding coordinates like you have
what do you get when you do that?
OpenStudy (anonymous):
-2/5
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jimthompson5910 (jim_thompson5910):
yep, that's what I got too
jimthompson5910 (jim_thompson5910):
so the slope is -2/5, which means that m = -2/5
jimthompson5910 (jim_thompson5910):
now plug this into y - y1 = m(x-x1)
OpenStudy (anonymous):
Oh
OpenStudy (anonymous):
y-1=-2/5(x-3)
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OpenStudy (anonymous):
does y = 2x + 7
jimthompson5910 (jim_thompson5910):
y-1=-2/5(x-3) is correct
jimthompson5910 (jim_thompson5910):
now convert to standard form, are you familiar with that?
OpenStudy (anonymous):
No I dont think so
jimthompson5910 (jim_thompson5910):
The idea is to convert y - y1 = m(x - x1) into the form
Ax + By = C
which is known as standard form
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OpenStudy (anonymous):
Oh
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
so how do we convert?
OpenStudy (anonymous):
well I don't know.
jimthompson5910 (jim_thompson5910):
To convert, follow the steps below
y-1=-2/5(x-3)
5y-5=-2(x-3)
5y-5=-2x+6
2x+5y = 6+5
2x+5y = 11
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OpenStudy (anonymous):
Ok, then after that convert to y=mx=b
jimthompson5910 (jim_thompson5910):
no that's it because they want it in standard form
OpenStudy (anonymous):
Oh, Ok let me see if it is right
OpenStudy (anonymous):
Awesome man... Can you show me how to do this problem?
jimthompson5910 (jim_thompson5910):
you mean go over it again?
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OpenStudy (anonymous):
No I have a new concept, and I am trying to study for a quiz.
Using the given equations, find the point of intersection. If there is no point of intersection, type no points .
6 x - 2 y = 5
3 x - y = 10
The lines intersect at
jimthompson5910 (jim_thompson5910):
what do you notice about the ratio between corresponding coefficients?
OpenStudy (anonymous):
They are the same is that what you mean?
jimthompson5910 (jim_thompson5910):
I mean what's the relationship between 6 and 3 (the x coefficients)?
OpenStudy (anonymous):
Ok I think I got it.
6x-2y=5
-2(3x-y=10)
6x-2y=5
-6x+2y=-20
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OpenStudy (anonymous):
Is that what we are looking for?
jimthompson5910 (jim_thompson5910):
yes now add the equations
OpenStudy (anonymous):
0+0=-15
jimthompson5910 (jim_thompson5910):
so you basically get 0 = -15, which is NEVER true
jimthompson5910 (jim_thompson5910):
so what does that mean?
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OpenStudy (anonymous):
So it is a no point? (As stated in the question)
jimthompson5910 (jim_thompson5910):
yes, there are no points of intersection
OpenStudy (anonymous):
Let me see if it correct... Lol
OpenStudy (anonymous):
Yup, I will figure this out... can you follow to see if I am correct?
OpenStudy (anonymous):
Using the given equations, find the point of intersection. If there is no point of intersection, type no points . Leave answers in fractional form.
3 x + 2 y = 6
4 x + y = 1
The lines intersect at __________
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