Question

PLEASe someone help me with cal problem!!

Answer 1

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. What is the distance covered before the car comes to a stop? (Give your answers correct to one decimal place.)

Answer 2

please!! help me....

Answer 3

thanks for taking a look...

Answer 4

55 = 220/3ft/s therefore speed = 220/3 - 44t ???

Answer 5

then anti-derivative?!

Answer 6

gimmie a second. Im trying to remember how to do this =p. I havnt done a problem like this in awhile

Answer 7

no problem.... take your time.. I just want to understand.

Answer 8

I believe you can do V^2/2

Answer 9

v = 0

Answer 10

velocity 1=50

Answer 11

right because the car is stopping...

Answer 12

oh initial velocity

Answer 13

velocity 2 = 0

Answer 14

acceleration is -44ft/s

Answer 15

1250-44t?

Answer 16

hmmm. I think you can use a different equation. Let me google it

Answer 17

v^2 - u^2 = 2 A S

Answer 18

You are trying to do this with calculus Im thinking of this more as phyisics lol.

Answer 19

yea... it would be easier as physics im sure.
is that the correct formula?

Answer 20

>.< I dont think Im much help to you.... I cant remember how to do this. =(. There are several people here who can do this in about 5 seconds but they are not online atm.

Answer 21

5280 / 3600 = 1.46666667
1.46666667*50=73.333

Answer 22

so thats in feet per second

Answer 23

what about using this... initial velocity is 50 mi/h, and acceleration is -44ft/s^2, d = ?. An equation to use would be Vf^2=Vi + 2ad.

Answer 24

0 = 50 * 2 * -44 * d

Answer 25

no...

Answer 26

ugh...

Answer 27

well I found your answer via google >.> but it was done with physics instead of calculus

Answer 28

what was the answer?

Answer 29

Im so sorry. Im not any help to you. Its pretty sad. Ive passed calculus 2 and I cant even remember how to do this problem. I need to brush up lol

Answer 30

http://answers.yahoo.com/question/index?qid=20090131110257AAFPP5l

Answer 31

its got to be around 63 or 64...

Answer 32

61.1 ft

Answer 33

ugh... my luck this is going to be on the test....

Answer 34

What is your test?

Answer 35

When?! Monday after thanksgiving break.

Answer 36

ewww

Answer 37

yea... whats your major?

Answer 38

computer science lol.

Answer 39

hahaha

Answer 40

This is an integration problem

Answer 41

50mi/h*hr/60min*min/60s*5280ft/mi
v(0)=73.3ft/s

Answer 42

i thought something like that...

Answer 43

a(t)=-42
v(t)=-42t+73.3
0=-42t+73.3
42t=73.3

Answer 44

t=73.3/42

Answer 45

grrr

Answer 46

44

Answer 47

will you do something for me real quick... my graphing calculator is messed up can you put in -9+ - square root 81 (4*4.97*-300) all over 2*4.97

Answer 48

lol sure. Let me get it out of my car lol brb

Answer 49

81 MINUS the ()

Answer 50

wait is this a quadratic?

Answer 51

yea

Answer 52

its another problem...

Answer 53

A stone is dropped from the top of a 300 m tower. (Acceleration due to gravity is -9.8 m/s2. Ignore air resistance. Give your answers correct to two decimal places.) (d) If the stone is thrown downward with a speed of 9 m/s, how long does it take to reach the ground?

Answer 54

\[-9\pm \sqrt{81-4*4.97*-300}\over2*4.97\]

Answer 55

good thing im taking physics next semester.
0=4.97t^2 +9t-300

Answer 56

did I input the equation right?

Answer 57

yes

Answer 58

hmmm I got an imaginary number!

Answer 59

4.97=a
9=b
300=c

Answer 60

ok make sure you put (4*4.97*-300)

Answer 61

using those gave me imagnary numer

Answer 62

-300!!!!!!

Answer 63

i have ten minutes...hurry

Answer 64

hmm okay x1 gave me 6.92 and x2 gave me -8.73

Answer 65

ok yaya

Answer 66

crap it was wrong :(

Answer 67

o well! thanks for your help!!!

Answer 68

Lol I wasnt any help. I feel bad.

Answer 69

=(

Answer 70

I need to go back yo calculus one lol

Answer 71

its ok!

Answer 72

No not really. I should remember how to that kind of problem. =(

Answer 73

I want to hang my self now =(

Answer 74

its been what two years for you?

Answer 75

one

Answer 76

3 semesters

Answer 77

I took calc one took calculus two and now Im in matrix theory.

Answer 78

I took a semester off over summer

Answer 79

you dont take cal3?

Answer 80

I cant take calculus 3 till Ive taken differential equations

Answer 81

What about you?

Answer 82

ok i was just wondering... wait wow i cant diff q until after cal 3

Answer 83

cant take

Answer 84

What are you in now?

Answer 85

Cal 1 but honestly I'm taking it to make a better grade, I made a C the first time around, so trying again to replace it

Answer 86

Cal 2 next sem, then cal 3 during the summer, diff q in the fall then BREATHER on MATH

Answer 87

cool my states curriculum follow
calc 1
calc 2
Matrix Theory or Differential Equations
calc 3
those are the core classes

then major choices of math courses

Answer 88

haha you have more math after that! Wow, thats crazy!