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10+2e^8x=30
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2e^8x=30-10=20, e^8x=20/2=10, applying log on both sides we get loge^8x=log10, 8x=log10, 8x=1 since log10 value is 1, x=1/8 is the answer
10+2e^(8x)=30 2e^(8x) = 20 e^(8x)= 10 8x = ln 10 \[x= \frac{\ln 10}{8}\]
shaik you have to take the natural log ( log base e) to cancel the e^(8x)
i have done right only know agreene?
bcz of taking log i got 1/8
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ln (10) = 2.302585092 not 1
i am talking about log not ln
log(10)=1
\[\log_{10} e^{8x} \neq 8x\]
you cant take log base 10. It just doesnt work that way.
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I HAVE NOT TAKEN BASE AS 10
log base 10 (10) = 1 but... thats not part of this equation you are dealing with natural logs. ln(10) = 2.30
but the thing is that is not one of the ancers
0.2878 c. 1.7006 1.8444 d. 10.0000
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