Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

10+2e^8x=30

OpenStudy (shaik0124):

2e^8x=30-10=20, e^8x=20/2=10, applying log on both sides we get loge^8x=log10, 8x=log10, 8x=1 since log10 value is 1, x=1/8 is the answer

OpenStudy (agreene):

10+2e^(8x)=30 2e^(8x) = 20 e^(8x)= 10 8x = ln 10 \[x= \frac{\ln 10}{8}\]

OpenStudy (agreene):

shaik you have to take the natural log ( log base e) to cancel the e^(8x)

OpenStudy (shaik0124):

i have done right only know agreene?

OpenStudy (shaik0124):

bcz of taking log i got 1/8

OpenStudy (agreene):

ln (10) = 2.302585092 not 1

OpenStudy (shaik0124):

i am talking about log not ln

OpenStudy (shaik0124):

log(10)=1

OpenStudy (agreene):

\[\log_{10} e^{8x} \neq 8x\]

OpenStudy (agreene):

you cant take log base 10. It just doesnt work that way.

OpenStudy (shaik0124):

I HAVE NOT TAKEN BASE AS 10

OpenStudy (agreene):

log base 10 (10) = 1 but... thats not part of this equation you are dealing with natural logs. ln(10) = 2.30

OpenStudy (anonymous):

but the thing is that is not one of the ancers

OpenStudy (anonymous):

0.2878 c. 1.7006 1.8444 d. 10.0000

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!