Question

Two fair dice are rolled . Find the probability that the total on the two dice is 8. Given that neither shows a five.

Answer 1

the probability is that it could be a 3

Answer 2

neither meaning none show 5

Answer 3

what do you mean by neither shows a 5 ? does the 5 is excluded from the sample space ?

Answer 4

{(4,4),(6,2),(2,6)} probility is 3

Answer 5

Given that neither die shows a five.

Answer 6

cool then 3/36 = 1/12

Answer 7

i got that answer tooo buh , unfortunately the answer is 1/4

Answer 8

then the question is not properly set I guess..

Answer 9

not possible
its from the cambridge book , it cant be

Answer 10

how?

Answer 11

Shouldn't it be: (6,2),(2,6),(4,4),(4,4)?

Answer 12

then it would be 4/ 36
so 1/9 . answer is still wrong

Answer 13

I'm also tempted to believe there must be a typo somewhere... or there's something we don't know.

Rolling the first dice and having it land on either 2, 4 or 6 gives a probability of 1/2.
The second dice then has a 1/6 probability of landing in such a way that it sums to 8 with the previous dice. This gives 1/12.

-.-

Answer 14

@across: (4,4) and (4,4) both are same events..

Answer 15

ooh Sweet , i got itt . :) yupiie
there are 3 outcomes (4|4) or ( 6|2)or (2|6)
so Each has probabilty 1/12
1/12 + 1/12+1/12
therefore 3/12
1/4

Answer 16

Landing a (4,4) has a probability of 1/12!?

Answer 17

o Each has probabilty 1/12 -- how ? :O

Answer 18

why don't u say(4,4) (4,4) as (6,2) (2,6)

Answer 19

3/36 = 1/12
1/12 x 3 coz 3 outcomes
1/4

Answer 20

duh ...... your probability skills are just wonderful.. congratulation.

Answer 21

1/12 is already the probability of landing a dice sum of 8 without taking 5 into consideration. Then you're multiplying this probability by 3? Are you casting the dice thrice?

Answer 22

Umm i dont knnow