Question

Solve the logarithmic equation.
log2(x-1) - log2(5x + 1) = -3
log2[(x-1)(5x + 1)] = -3
(x-1)(5x + 1) = 2^-3
5x^2 - 5x - 1 = 1/8
5x^2 + 4x - 7/8 = 0

This class is killing me.

Answer 1

I was trying to follow along with my book. But of course the only give easy examples.

Answer 2

is it the log to base 2?

Answer 3

log2+log(x-1)-log2-log(5x+1)=-3
or, log(x-1)-log(5x+1)=-3
or, log((x-1)/(5x+1))=-3
or, (x-1)/(5x+1)=2pow(-3)=1/8
now try to find the value of x

Answer 4

yes.