Question

what is the derivative of 1/t^2

Answer 1

with respect to what??

Answer 2

d/dx(1/t^2) = \[-\frac{2}{t^3}\]

Answer 3

implied t argument

Answer 4

with respect to y.

Answer 5

so the ans will be -2/t^2*(dt/dy)

Answer 6

how did you get that?

Answer 7

im so confused

Answer 8

y = 1/t^2 + t^1/2 this is the real equation. i got the second part but i cant get the fist part

Answer 9

actually first of all y find out d/dt(1/t^2) as there is no terms of y so to make it w.r.t y just multiply wit dy/dy..then actual equ stands d/dy(1/t^2)*(dy/dt).

Answer 10

the ans will be y=-2/t^3*(dy/dt)+1/2*(dy/dt)

Answer 11

ok thank you

Answer 12

most welcome!!

Answer 13

i miss some terms in 2nd part ur ans is
y=-2/t^3*(dy/dt)+1/2*1/t^(1/2)*(dy/dt)